document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=445406>Question 445406</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A father is 3 times older than his son now. In 10 years time their combined ages will b 68. How old are they now? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #306798 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=306798\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> son =x<BR>\n" );
document.write( "father = 3x<BR>\n" );
document.write( "..<BR>\n" );
document.write( "after 10 years<BR>\n" );
document.write( "son = x+10<BR>\n" );
document.write( "father= 3x+10<BR>\n" );
document.write( "...<BR>\n" );
document.write( "x+10+3x+10= 68<BR>\n" );
document.write( "4x+20=68<BR>\n" );
document.write( "4x=48<BR>\n" );
document.write( "x=12 yera son's age<BR>\n" );
document.write( "father = 36 years<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );