document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=445151>Question 445151</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello I'm having difficulty trying to solve this rate/distance/time problem if you could help me that would be grate. Thank you.\r<BR>\n" );
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document.write( "Two cars, which are 510 miles apart and whise speeds differ by 6 miles per hour, are moving towards each other. if they meet in 5 hours, find the speed of each car.\r<BR>\n" );
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document.write( "thank you again </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #306733 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=306733\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> their rate of closure is ___ 510 / 5 or 102 mph ___ this is the sum of the speeds\r<BR>\n" );
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document.write( "s + s+6 = 102 ___ 2s + 6 = 102 ___ 2s = 96 ___ s = 48\r<BR>\n" );
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document.write( "so the two speeds are 48 and 54 </SPAN>\n" );
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