document.write( "Question 46223: Can someone help me?!?! How can I find the dimensions of a rectangular box with a width three times the height, the length is 6 inches more than the height, and the volume is 15 cubic inches? \r
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Algebra.Com's Answer #30673 by venugopalramana(3286)\"\" \"About 
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How can I find the dimensions of a rectangular box with a width=W three times the height=H, the length=L is 6 inches more than the height, and the volume=V is 15 cubic inches?
\n" ); document.write( "W=3*H
\n" ); document.write( "L=H+6
\n" ); document.write( "V=15=LWH=(H+6)3*H*H=3H^3+18H^2
\n" ); document.write( "H^3+6H^2-5=0
\n" ); document.write( "H+1 IS A FACTOR
\n" ); document.write( "-1|1....6.....0.....-5
\n" ); document.write( "...0...-1....-5......5
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\n" ); document.write( "...1....5.....-5....0
\n" ); document.write( "H^2+5H-5=0
\n" ); document.write( "H={-5+SQRT(25-20)}/2
\n" ); document.write( "=-VE. CHECK THE PROBLEM.....DATA GIVEN DOES NOT LEAD TO A FEASIBLE SOLUTION
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