document.write( "Question 445091: the length of a rectangle is one inch more than twice the width. The perimeter is 110 inches. Find the length and the width of the rectangle \n" ); document.write( "
Algebra.Com's Answer #306717 by chriswen(106)\"\" \"About 
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Let x in be the width.
\n" ); document.write( "Let 2x+1 in be the width.
\n" ); document.write( "...
\n" ); document.write( "P=2(l+w)
\n" ); document.write( "110=2(2x+1+x)
\n" ); document.write( "110=2(3x+1)
\n" ); document.write( "110/2=3x+1
\n" ); document.write( "55=3x+1
\n" ); document.write( "3x=55-1
\n" ); document.write( "3x=54
\n" ); document.write( "x=54/3
\n" ); document.write( "x=18
\n" ); document.write( "2x+1=37
\n" ); document.write( "...
\n" ); document.write( "Therefore, the length of the rectangle is 37 in and the width is 18 in.
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