document.write( "Question 445091: the length of a rectangle is one inch more than twice the width. The perimeter is 110 inches. Find the length and the width of the rectangle \n" ); document.write( "
Algebra.Com's Answer #306717 by chriswen(106)![]() ![]() ![]() You can put this solution on YOUR website! Let x in be the width. \n" ); document.write( "Let 2x+1 in be the width. \n" ); document.write( "... \n" ); document.write( "P=2(l+w) \n" ); document.write( "110=2(2x+1+x) \n" ); document.write( "110=2(3x+1) \n" ); document.write( "110/2=3x+1 \n" ); document.write( "55=3x+1 \n" ); document.write( "3x=55-1 \n" ); document.write( "3x=54 \n" ); document.write( "x=54/3 \n" ); document.write( "x=18 \n" ); document.write( "2x+1=37 \n" ); document.write( "... \n" ); document.write( "Therefore, the length of the rectangle is 37 in and the width is 18 in. \n" ); document.write( " |