document.write( "Question 445047: Doris invested some money at 7% and some money at 5% She invested 6,000 more at 5% than she did at 7% Her total yearly interest from the two investments was 600 How much did Doris invest at each rate?
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Algebra.Com's Answer #306671 by checkley79(3341)\"\" \"About 
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.07x+.05(x+6,000)=600
\n" ); document.write( ".07x+.05x+300=600
\n" ); document.write( ".12x=600-300
\n" ); document.write( ".12x=300
\n" ); document.write( "x=300/.12
\n" ); document.write( "x=$2,500 amount invested @ 7%.
\n" ); document.write( "2,500+6,000=$ 8,500 amount invested @ 5%.
\n" ); document.write( "Proof:
\n" ); document.write( ".07*2,500+.05*8,500=600
\n" ); document.write( "175+425=600
\n" ); document.write( "600=600
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