document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=46225>Question 46225</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can someone help me with logarithms?!?! I need to solve the equation (6 + 6 lnx = 11) by isolating the natural logarithm and exponentiating both sides, expressing the answer in terms of e. Any explanation would be extremely helpful as I am not even sure where to start!!\r<BR>\n" );
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document.write( "Thank You!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #30667 by </B><A HREF=/tutors/aboutme.mpl?userid=Nate><B>Nate(3500)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=30667\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6 + 6ln(x) = 11<BR>\n" );
document.write( "6ln(x) = 5<BR>\n" );
document.write( "ln(x) = 5/6<BR>\n" );
document.write( "x = e^(5/6) </SPAN>\n" );
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