document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=444957>Question 444957</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 4x^2-146x+520=0<BR>\n" );
document.write( "(2x- )(2x- )\r<BR>\n" );
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document.write( "I can't seem to find the missing #'s <BR>\n" );
document.write( "HELP PLEASE!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #306660 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=306660\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We can first divide through by 2:<BR>\n" );
document.write( "2x^2 - 73x + 260 = 0<BR>\n" );
document.write( "The constant term 260 has factors 130 and 2 and 65 and 4.<BR>\n" );
document.write( "Recognizing that 73 = 65 + 4*2 and the first factor starts with 2x, we use the last 2 factors:<BR>\n" );
document.write( "2x^2 - 73x + 260 = (2x - 65)(x - 4)<BR>\n" );
document.write( "Now solve for x:<BR>\n" );
document.write( "(2x - 65)(x - 4) = 0<BR>\n" );
document.write( "x = 4<BR>\n" );
document.write( "2x - 65 = 0 -> x = 65/2 = 32 1/2<BR>\n" );
document.write( "Ans: x = 4, 32 1/2<BR>\n" );
document.write( "Check using original expression:<BR>\n" );
document.write( "4(4)^2 - 146(4) + 520 = 0<BR>\n" );
document.write( "4(32.5)^2 - 146(32.5) + 520 = 0 </SPAN>\n" );
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