document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=444828>Question 444828</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the value of x so the line that passes through (x, 5) and (12, 2) is perpendicular to the line that passes through (0, 1) and (2, 7).  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #306651 by </B><A HREF=/tutors/aboutme.mpl?userid=rwm><B>rwm(914)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rwm><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=306651\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> slope of second line<BR>\n" );
document.write( "(7-1)/(2-0)<BR>\n" );
document.write( "slope of first line<BR>\n" );
document.write( "(5-2)/(x-12)<BR>\n" );
document.write( "we want the two slopes multiplied to equal -1<BR>\n" );
document.write( "(7-1)/(2-0)*(5-2)/(x-12)=-1<BR>\n" );
document.write( "it looks harder than it is.<BR>\n" );
document.write( "just do the math.<BR>\n" );
document.write( "6/2*3/(x-12)=-1<BR>\n" );
document.write( "9/x-12=-1<BR>\n" );
document.write( "9=-1*(x-12)<BR>\n" );
document.write( "-9=x-12<BR>\n" );
document.write( "add 12<BR>\n" );
document.write( "3=x\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );