document.write( "Question 444908: NEED HELP!!!\r
\n" ); document.write( "\n" ); document.write( "A person is chosing between 2 cellular phone plans. One has a monthly fee of $50 for 500 minutes plus $0.35 for each minute over the 500. The second plan has a monthly fee of $75 for 1000 minutes plus $0.45 for each minute over the 1000.\r
\n" ); document.write( "\n" ); document.write( "After how many minutes used are the monthly costs of the plans equal?
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Algebra.Com's Answer #306605 by htmentor(1343)\"\" \"About 
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Let C1 = the cost of plan 1
\n" ); document.write( "Let C2 = the cost of plan 2
\n" ); document.write( "Let x = the number of minutes used
\n" ); document.write( "For the costs of the two plans we can write:
\n" ); document.write( "C1 = 50 + 0.35(x - 500) [x >= 500]
\n" ); document.write( "C2 = 75 + 0.45(x - 1000) [x >= 1000]
\n" ); document.write( "Set C1 = C2, since the costs are equal:
\n" ); document.write( "50 + 0.35(x - 500) = 75 + 0.45(x - 1000)
\n" ); document.write( "Solve for x:
\n" ); document.write( "50 + 0.35x - 175 = 75 + 0.45x - 450
\n" ); document.write( "0.1x = 250
\n" ); document.write( "x = 2500
\n" ); document.write( "Ans: 2500 minutes
\n" ); document.write( "Check:
\n" ); document.write( "C1 = 50 + 0.35(2500-500) = 50 + 700 = 750
\n" ); document.write( "C2 = 75 + 0.45(2500-1000) = 75 + 675 = 750
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