document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=444904>Question 444904</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this equation: the measure of the supplement of an angle is 60 degrees less than twice the measure of the angle. Find the measures of both angles. (algebraic solution) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #306603 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=306603\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> By definition, supplementary angles add up to 180.  So we have two angles. Let's call them A and B. Now we are given an angle. Its measure is 2B - 60. Let's call this A.  Then by definition, 2B - 60 + B = 180.  Solve for B.  Then:<BR>\n" );
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document.write( "3B = 240,  B = 80.<BR>\n" );
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document.write( "Since we know B = 80 and we have an expression for A,  A= 2B-60, then:<BR>\n" );
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document.write( "A = 2(80) - 60 <BR>\n" );
document.write( "A= 100\r<BR>\n" );
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document.write( "So our two angles are 100 and 80, which obviously add up to 180. </SPAN>\n" );
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