document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=444718>Question 444718</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The diagonal of a square is 2 meters longer than a side.  Find the length of a side.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #306492 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=306492\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If s is the (common) side of a square, then the diagonal is given by <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%282%29%2As ALIGN=MIDDLE  ALT=\"sqrt%282%29%2As\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Hence by hypothesis <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%282%29%2As+=+s+%2B+2 ALIGN=MIDDLE  ALT=\"sqrt%282%29%2As+=+s+%2B+2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "==> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28sqrt%282%29+-+1%29s+=+2 ALIGN=MIDDLE  ALT=\"%28sqrt%282%29+-+1%29s+=+2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=s+=+2%2F%28sqrt%282%29+-+1%29 ALIGN=MIDDLE  ALT=\"s+=+2%2F%28sqrt%282%29+-+1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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