document.write( "Question 444638: The sum of the digits of a two digit number is 15. If the digits are interchanged, the number is increased by nine. What is the original number? \n" ); document.write( "
Algebra.Com's Answer #306446 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! These are fun problems because they force you to reconsider what numbers mean. \n" ); document.write( "Consider 15. What does it mean? \n" ); document.write( "Well, the 1 means 1*10. \n" ); document.write( "And the 5 means 5*1. \n" ); document.write( "So 15 means 1*10 + 5*1 = 10 + 5 = 15. \n" ); document.write( "We can extend this notion to any sequence of letters, for example 'xy'. \n" ); document.write( ". \n" ); document.write( "Do NOT get confused with 'xy' meaning x * y. \n" ); document.write( "Here it would mean 10*x + 1*y. \n" ); document.write( ". \n" ); document.write( "xy = the two-digit number, which \n" ); document.write( "x + y = 15 \n" ); document.write( "yx = xy + 9 \n" ); document.write( ". \n" ); document.write( "Looking back we realize that x and y have to be single digits. And for them to = 15, they're either \n" ); document.write( "9 + 6 \n" ); document.write( "8 + 7 \n" ); document.write( "7 + 8 \n" ); document.write( "6 + 9 \n" ); document.write( ". \n" ); document.write( "When the numbers are reversed, the difference is 9. \n" ); document.write( ". \n" ); document.write( "Take 78, when turned around it is 87, which is 9 more. \n" ); document.write( ". \n" ); document.write( "So xy = 78, which is the original number. \n" ); document.write( "The sum 7+8 = 15. \n" ); document.write( "When the order is reversed (i.e., 87) the value is 9 more than before the reversal. \n" ); document.write( " |