document.write( "Question 444500: A rectangular movie screen has an area of 9,315 square feet. Find the dimensions of the screen if it is 18 feet longer than it is wide. \n" ); document.write( "
Algebra.Com's Answer #306387 by chriswen(106)![]() ![]() ![]() You can put this solution on YOUR website! Let x be the width. \n" ); document.write( "Let x + 18 be the length. \n" ); document.write( "... \n" ); document.write( "A=l*w \n" ); document.write( "9315=(x+18)(x) \n" ); document.write( "9315=x^2+18x \n" ); document.write( "0=x^2+18x-9315 \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "... \n" ); document.write( "So, x is the positive number as we are dealing with positive values. \n" ); document.write( "x=87.9329665284211 \n" ); document.write( "x+18=105.9329665284211 \n" ); document.write( "So therefore, the rectangle movie screen is roughly 88 ft by 106 ft. \n" ); document.write( " |