document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=444481>Question 444481</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3^6x=2^(-x-4)\r<BR>\n" );
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document.write( "using base-10 logarithms </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #306366 by </B><A HREF=/tutors/aboutme.mpl?userid=chriswen><B>chriswen(106)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chriswen><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=306366\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3^6x=2^(-x-4)<BR>\n" );
document.write( "log3^6x=log2^(-x+4) ... log both sides<BR>\n" );
document.write( "6xlog3=(-x+4)log2 ... since, logm^n=nlogm<BR>\n" );
document.write( "6xlog3=-xlog2+4log2 ... distribution<BR>\n" );
document.write( "6xlog3+xlog2=4log2<BR>\n" );
document.write( "x(6log3+log2)=4log2<BR>\n" );
document.write( "x=4log2/(6log3+log2) ... now you can just input this into your calculator or you can simplify it more.<BR>\n" );
document.write( "x=.380598 </SPAN>\n" );
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