document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=443329>Question 443329</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Prove that each is an identity\r<BR>\n" );
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document.write( "(sin 2 x + sin x)/ (cos 2 x + cos x + 1) = tan x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #306341 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=306341\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Prove that each is an identity <BR>\n" );
document.write( "(sin 2 x + sin x)/ (cos 2 x + cos x + 1) = tan x<BR>\n" );
document.write( "..<BR>\n" );
document.write( "sin2x+sinx/cos2x+cosx+1=tanx<BR>\n" );
document.write( "start with left side<BR>\n" );
document.write( "2sinxcosx+sinx/cos^2x-sin^2x+cosx+1<BR>\n" );
document.write( "sinx(2cosx+1)/cos^2x-1+cos^2x+cosx+1<BR>\n" );
document.write( "sinx(2cosx+1)/2cos^2x+cosx<BR>\n" );
document.write( "sinx(2cosx+1)/cosx(2cosx+1)<BR>\n" );
document.write( "sinx/cosx=tanx<BR>\n" );
document.write( "left side=right side </SPAN>\n" );
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