document.write( "Question 444371: one side of a rectangle is 8 cm more than the other. If the diagonal of the rectangle is 40 cm, find the dimensions of the rectangle \n" ); document.write( "
Algebra.Com's Answer #306330 by poliphob3.14(115)\"\" \"About 
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Lts the width x cm, then the length will be: x+8 cm.Since the diagonal is 40 cm\r
\n" ); document.write( "\n" ); document.write( "using Pythagorean theorem we write the equation:\"x%5E2%2B%28x%2B8%29%5E2=40%5E2\", setting \r
\n" ); document.write( "\n" ); document.write( "to zero and solving this quadratic equation:\"2x%5E2%2B16x-1536=0\" or\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B8x-768=0\",we get x=24.\r
\n" ); document.write( "\n" ); document.write( "Answer: The dimensions of the rectangle are 24cm, and ,24+8=32cm.
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