document.write( "Question 444169: There is a 0.9968 probability that a randomly selected 50-year-old female lives through the year (based on data from the U.S. Department of Health and Human Services). A Fidelity life insurance company charges $226 for insuring that the female will live through the year. If she does not survive the year, the policy pays out $50,000 as a death benefit.\r
\n" ); document.write( "\n" ); document.write( "From the perspective of the 50-year-old female, what are the values corresponding to the two events of surviving the year and not surviving?
\n" ); document.write( "If a 50-year-old female purchases the policy, what is her expected value?\r
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\n" ); document.write( "In the event she lives, the value is -$226. In the event she dies, the value is $49,774.\r
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Algebra.Com's Answer #306282 by stanbon(75887)\"\" \"About 
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There is a 0.9968 probability that a randomly selected 50-year-old female lives through the year (based on data from the U.S. Department of Health and Human Services).
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\n" ); document.write( "A Fidelity life insurance company charges $226 for insuring that the female will live through the year. If she does not survive the year, the policy pays out $50,000 as a death benefit.
\n" ); document.write( "From the perspective of the 50-year-old female, what are the values corresponding to the two events of surviving the year and not surviving?
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\n" ); document.write( "Ans: -226 ; 50,000-226 = 49774
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\n" ); document.write( "If a 50-year-old female purchases the policy, what is her expected value?
\n" ); document.write( "WORK TRIED:
\n" ); document.write( "In the event she lives, the value is -$226. In the event she dies, the value is $49,774.
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\n" ); document.write( "E(x) = 0.9968*(-226) + 0.0032(49774) = -$66
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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