document.write( "Question 444212: I dont knw how to solve the equations and check them : help? My Teacher Gave me 50 probelms of these . i am only asking to do those so maybe after i knw how to do the rest of the 45 problems\r
\n" ); document.write( "\n" ); document.write( "1. x/2=x+1/4 --> have to solve and check I tryed to like elimate the bottom to like 2 because 2 can go into 4 so i thought the bottom woulve be 2 then i thought the top would be x^2+1 soo maybe the answer would be x^2+1/2?\r
\n" ); document.write( "\n" ); document.write( "2. 3/x-1=4/3x+2 ^^\r
\n" ); document.write( "\n" ); document.write( "3. 3x/x+1=0 ^^\r
\n" ); document.write( "\n" ); document.write( "4.3/x-1=1/x^2-1 \r
\n" ); document.write( "\n" ); document.write( "Please Help me this is 75% of my grade AND its not even a test :(
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Algebra.Com's Answer #306275 by Leaf W.(135)\"\" \"About 
You can put this solution on YOUR website!
1. \"x%2F2+=+%28x%2B1%29%2F4\"
\n" ); document.write( "Find the least common denominator (LCD) between 2 and 4... 4. Multiply the entire equation by this LCD: \"4%28x%2F2%29+=+%28%28x%2B1%29%2F4%294\"
\n" ); document.write( "Simplify: \"2x+=+x+%2B+1\"
\n" ); document.write( "Solve for x by subtracting x from both sides: \"x+=+1\"
\n" ); document.write( "Therefore, x = 1
\n" ); document.write( "2. \"3%2F%28x-1%29+=+4%2F%283x+%2B+2%29\"
\n" ); document.write( "Find the LCD between x-1 and 3x+2... (x-1)(3x+2) Multiply the entire equation by this LCD: \"%28x-1%29%283x%2B2%29%283%2F%28x-1%29%29+=+%28x-1%29%283x%2B2%29%284%2F%283x%2B2%29%29\"
\n" ); document.write( "Simplify (NOTE: the (x-1) and /(x-1) cancel each other out, and the same with the (3x+2) and /(3x+2)): \"3%283x%2B2%29+=+4%28x-1%29\"
\n" ); document.write( "Distribute: \"9x%2B6+=+4x-4\"
\n" ); document.write( "Subtract 6 from both sides: \"9x+=+4x-10\"
\n" ); document.write( "Subtract 4x from both sides: \"5x+=+-10\"
\n" ); document.write( "Divide both sides by 5: \"x+=+-2\"
\n" ); document.write( "Therefore, x = -2
\n" ); document.write( "3. \"3x%2F%28x%2B1%29+=+0\"
\n" ); document.write( "Since there is only one denominator, the LCD is x+1.
\n" ); document.write( "\"%28x%2B1%29%283x%2F%28x%2B1%29%29+=+0%28x%2B1%29\"
\n" ); document.write( "Simplify (NOTE: The (x+1) and /(x+1) cancel each other out, and 0 multiplied by anything is 0): \"3x+=+0\"
\n" ); document.write( "Divide both sides by 3: \"x+=+0\"
\n" ); document.write( "Therefore, x = 0
\n" ); document.write( "4. \"3%2F%28x-1%29+=+1%2F%28x%5E2+-+1%29\"
\n" ); document.write( "Factor the denominator (\"x%5E2+-+1\" is a difference of squares, so (x+1)(x-1)): \"3%2F%28x-1%29+=+1%2F%28x%2B1%29%28x-1%29\"
\n" ); document.write( "Find the LCD between x-1 and (x+1)(x-1)... (x+1)(x-1). Multiply the entire equation by this: \"%28x%2B1%29%28x-1%29%283%2F%28x-1%29%29+=+%28x%2B1%29%28x-1%29%281%2F%28x%2B1%29%28x-1%29%29\"
\n" ); document.write( "Simplify: \"3%28x%2B1%29+=+1\"
\n" ); document.write( "Distribute: \"3x+%2B+3+=+1\"
\n" ); document.write( "Subtract 3 from both sides: \"3x+=+-2\"
\n" ); document.write( "Divide both sides by 3: \"x+=+-2%2F3\"
\n" ); document.write( "Therefore, \"x+=+-2%2F3\"
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