document.write( "Question 444189: Please help me solve these problems:\r
\n" ); document.write( "\n" ); document.write( "Given the probability distribution of a random variable
\n" ); document.write( "outcome: -2, 4, 10
\n" ); document.write( "probability: 0.80, 0.15, 0.05\r
\n" ); document.write( "\n" ); document.write( "3. Compute the expected value (one digit after decimal point).
\n" ); document.write( "4. Compute the variance (two digits after decimal point).
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Algebra.Com's Answer #306266 by htmentor(1343)\"\" \"About 
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The expected value of a discrete random variable x is
\n" ); document.write( "\"E%28x%29+=+sum%28+x%5Bi%5Dp%5Bi%5D%2C+i%29\" where \"x%5Bi%5D\" are the outcomes and \"p%5Bi%5D\" are their probabilities
\n" ); document.write( "Using the values x = -2, 4, 10; p = 0.8, 0.15, 0.05, we get
\n" ); document.write( "E(x) = -2*0.8 + 4*0.15 + 10*0.05 = -0.5
\n" ); document.write( "The variance of a discrete random variable x is
\n" ); document.write( "\"sigma%5E2+=+sum%28%28x%5Bi%5D+-+E%28x%29%29%5E2%2Ap%5Bi%5D%2Ci%29\"
\n" ); document.write( "So we have
\n" ); document.write( "\"sigma%5E2\" = (-2 - -0.5)^2 + (4 - -0.5)^2 + (10 - -0.5)^2 = 10.35
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