document.write( "Question 444174: The perimeter of a rectangle is 38m. The length is 10m more than twice the width. Find the dimensions. \n" ); document.write( "
Algebra.Com's Answer #306264 by chriswen(106)\"\" \"About 
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Let x m be the width.
\n" ); document.write( "Let 2x+10 m be the length.
\n" ); document.write( "...
\n" ); document.write( "P=2(l+w)
\n" ); document.write( "38=2(2x+10+x)
\n" ); document.write( "38=2(3x+10)
\n" ); document.write( "38=6x+20
\n" ); document.write( "6x=38-20
\n" ); document.write( "6x=18
\n" ); document.write( "x=18/6
\n" ); document.write( "x=3
\n" ); document.write( "2x+10=16\r
\n" ); document.write( "\n" ); document.write( "Therefore, the rectangle is 3m by 16m.
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