document.write( "Question 444174: The perimeter of a rectangle is 38m. The length is 10m more than twice the width. Find the dimensions. \n" ); document.write( "
Algebra.Com's Answer #306264 by chriswen(106)![]() ![]() ![]() You can put this solution on YOUR website! Let x m be the width. \n" ); document.write( "Let 2x+10 m be the length. \n" ); document.write( "... \n" ); document.write( "P=2(l+w) \n" ); document.write( "38=2(2x+10+x) \n" ); document.write( "38=2(3x+10) \n" ); document.write( "38=6x+20 \n" ); document.write( "6x=38-20 \n" ); document.write( "6x=18 \n" ); document.write( "x=18/6 \n" ); document.write( "x=3 \n" ); document.write( "2x+10=16\r \n" ); document.write( "\n" ); document.write( "Therefore, the rectangle is 3m by 16m. \n" ); document.write( " |