document.write( "Question 444160: My probelm is this: A truck enters a highway driving 60mph. A car enters the highway at the same place 12 minutes later and drives 67mph in the same direction. How long before the car passes the truck?\r
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document.write( "I have My Math Lab on coursecompass.com and it kind of explains the solving process but I seem to get lost at the end. \r
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document.write( "I know that the problem needs to be set up with d(t)=60(t + 10) and d(c)=67t but after that I get lost. Please help. \n" );
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Algebra.Com's Answer #306242 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Truck 60 mph \n" ); document.write( "Car 67 mph \n" ); document.write( "Difference in time=00:12mins 0.2 hours \n" ); document.write( "Truck will have covered 0.2 miles before Car enters the highway \n" ); document.write( " \n" ); document.write( "catch up distance= 0.2 miles \n" ); document.write( "catch up speed = 67-60 mph \n" ); document.write( "catch up speed = 7 mph \n" ); document.write( " \n" ); document.write( "Catchup time = catchup distance/catch up speed \n" ); document.write( "catch up time= 0.2 / 7 \n" ); document.write( "catch up time= 0.03 hours \n" ); document.write( "catch up time= 1.71 minutes \n" ); document.write( "..\r \n" ); document.write( "\n" ); document.write( "The other method \n" ); document.write( "let the car meet after time = t hours \n" ); document.write( "time truck takes = 12 minutes more (t+0.2)hours \n" ); document.write( "Distance same \n" ); document.write( "D= r*t \n" ); document.write( "67*t = 60*(t+0.2) \n" ); document.write( "67t=60t+12 \n" ); document.write( "7t= 12 \n" ); document.write( "t=12/7 \n" ); document.write( "1.71 hours\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |