document.write( "Question 46158: I am having problems completing this problem.
\n" ); document.write( "Solve by completing square root. Equation has real number solutions.\r
\n" ); document.write( "\n" ); document.write( "3p^2-12p-10=0\r
\n" ); document.write( "\n" ); document.write( "So far I have worked it to:
\n" ); document.write( "p^2-12p/3-10/3=0\r
\n" ); document.write( "\n" ); document.write( "p^2-4p-10/3=0\r
\n" ); document.write( "\n" ); document.write( "where do I go from here? \n" ); document.write( "

Algebra.Com's Answer #30624 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
Solve by \"completing the square\":
\n" ); document.write( " $\"3p%5E2-12p-10+=+0\"$ Your first step is correct! Divide everything by 3 to make the coefficient of $\"P%5E2\"$ = 1.
\n" ); document.write( " $\"p%5E2-4p-10%2F3+=+0\"$ Now add $\"10%2F3\"$ from both sides.
\n" ); document.write( " $\"p%5E2-4p+=+10%2F3\"$ Now add the \"square of half the coefficient of p\" to both sides of the equation, that's $\"%28-4%2F2%29%5E2+=+4\"$ .
\n" ); document.write( " $\"p%5E2-4p%2B4+=+4%2B10%2F3\"$ Now factor the left side and simplify the right side.
\n" ); document.write( " $\"%28p-2%29%28p-2%29+=+22%2F3\"$
\n" ); document.write( " $\"%28p-2%29%5E2+=+22%2F3\"$ Take the square root of both sides.
\n" ); document.write( " $\"p-2+=+%2Bsqrt%2822%2F3%29\"$ or $\"p-2+=+-sqrt%2822%2F3%29\"$ Add 2 to both sides of these two equations.
\n" ); document.write( " $\"p+=+2%2B-sqrt%2822%2F3%29\"$ \n" ); document.write( "

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