document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=443780>Question 443780</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In still water, a boat averages 8 miles per hour. It takes the same amount of time to travel 30 miles downstream, with the current, as 18 miles upstream, against the current. What is the rate of the water's current? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #306204 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=306204\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> n still water, a boat averages 8 miles per hour. It takes the same amount of time to travel 30 miles downstream, with the current, as 18 miles upstream, against the current. What is the rate of the water's current.<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Let c=speed of current in mph<BR>\n" );
document.write( "c+8=speed of boat downstream in mph<BR>\n" );
document.write( "c-8=speed of boat upstream in mph<BR>\n" );
document.write( "Travel time= distance/speed<BR>\n" );
document.write( "30/8+c=18/8-c<BR>\n" );
document.write( "240-30c=144+18c<BR>\n" );
document.write( "48c=96<BR>\n" );
document.write( "c=2 mph<BR>\n" );
document.write( "ans<BR>\n" );
document.write( "rate of water's current = 2 mph </SPAN>\n" );
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