document.write( "Question 444067: A rectangle is 5 feet longer than twice
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document.write( "its width. If the rectangle has a perimeter of 88 feet,
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document.write( "what are the dimensions of the rectangle? \n" );
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Algebra.Com's Answer #306203 by chriswen(106)![]() ![]() ![]() You can put this solution on YOUR website! Let x ft be the width \n" ); document.write( "Let 2x+5 ft be the length\r \n" ); document.write( "\n" ); document.write( "P=2(x+2x+5) \n" ); document.write( "88=2(3x+5) \n" ); document.write( "88=6x+10 \n" ); document.write( "6x=88-10 \n" ); document.write( "6x=78 \n" ); document.write( "x=13 \n" ); document.write( "2x+5 \n" ); document.write( "=2(13)+5 \n" ); document.write( "=26+5 \n" ); document.write( "=31\r \n" ); document.write( "\n" ); document.write( "Therefore, the rectangle is 31ft by 13ft. \n" ); document.write( " |