document.write( "Question 444067: A rectangle is 5 feet longer than twice
\n" ); document.write( "its width. If the rectangle has a perimeter of 88 feet,
\n" ); document.write( "what are the dimensions of the rectangle?
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Algebra.Com's Answer #306203 by chriswen(106)\"\" \"About 
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Let x ft be the width
\n" ); document.write( "Let 2x+5 ft be the length\r
\n" ); document.write( "\n" ); document.write( "P=2(x+2x+5)
\n" ); document.write( "88=2(3x+5)
\n" ); document.write( "88=6x+10
\n" ); document.write( "6x=88-10
\n" ); document.write( "6x=78
\n" ); document.write( "x=13
\n" ); document.write( "2x+5
\n" ); document.write( "=2(13)+5
\n" ); document.write( "=26+5
\n" ); document.write( "=31\r
\n" ); document.write( "\n" ); document.write( "Therefore, the rectangle is 31ft by 13ft.
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