document.write( "Question 443978: My teacher has told me that it is impossible to find a domain for equations like:\r
\n" ); document.write( "\n" ); document.write( "sqrt(-1-2x)
\n" ); document.write( "sqrt(-2x-4)\r
\n" ); document.write( "\n" ); document.write( "I can't understand why the domain would not be (-∞, -½) and (-∞, -2). I was told that finding a domain was impossible because both elements in the equation were negative (-1 and -2x; -2x and -4). However, because x is an unknown and could be negative, I don't quite see how what I was told is possible. Is the variable x not considered when finding domains?
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Algebra.Com's Answer #306158 by swincher4391(1107)\"\" \"About 
You can put this solution on YOUR website!
It doesn't sound like your teach knows what they're talking about.\r
\n" ); document.write( "\n" ); document.write( "There are multiple ways to find the domains of these functions:\r
\n" ); document.write( "\n" ); document.write( "One find the inverse of the function's range (which is the original's domain)
\n" ); document.write( "Two solve for where x is defined.\r
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\n" ); document.write( "For \"sqrt%28-1-2x%29\" it is defined strictly where \"-1-2x+%3E=+0\"
\n" ); document.write( "So solve for x to get \"-1+%3E=+2x\" \"-1%2F2%3E=x%7D%7D+%7B%7B%7Bx%3C=+-1%2F2\"
\n" ); document.write( "From -\"infinity\" to \"-1%2F2\" is the domain.
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\n" ); document.write( "You can find the inverse as well. \"y+=+sqrt%28-1-2x%29\" \"y%5E2+=+-1-2x\"
\n" ); document.write( "\"y%5E2+%2B+1+=+-2x\" \"-1%2A%28y%5E2%2B1%29%2F2+=+x\"
\n" ); document.write( "Switch the xs and ys to get
\n" ); document.write( "\"y+=+expr%28-1%2F2%29%28x%5E2%2B1%29\"
\n" ); document.write( "Since the range of \"%28x%5E2%2B1%29\" is \"x%3E=1\" then if you multiplied all values by -1/2, you'd get \"x%3C=-1%2F2\" which is the same as what we had.
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\n" ); document.write( "I believe the argument you teacher may have tried to make is:\r
\n" ); document.write( "\n" ); document.write( "\"sqrt%28-1-2x%29+=+sqrt%28-1%2A%281%2B2x%29%29+=+sqrt%28-1%29+%2A+sqrt%281%2B2x%29\"
\n" ); document.write( "Since \"sqrt%28-1%29\" is not allowed, then you can't find the domain. But this is not true. \"sqrt%28-1%2A%281%2B2x%29%29\" is defined where \"%281%2B2x%29%3C=+0\", because a negative times a negative gives us a positive (which we can take the square root of). So \"%281%2B2x%29+%3C=+0\" \"+1+%3C+-2x\" \"-1%2F2+%3E=+x\" \"x+%3C=+-1%2F2\"... again gives us the same result.
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\n" ); document.write( "Thus you can find the domain.
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\n" ); document.write( "Does this make sense? I hope this helped.
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