document.write( "Question 46104: An Investment is worth $ 3432 in 1991. By 1995 it as grown to $ 4132. Let y be the value of the investment in the year x, where x = 0 represents 1991. Write a linear equation that models the value of the investment in the year x.\r
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Algebra.Com's Answer #30614 by Nate(3500)\"\" \"About 
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P(0,3432) and P(4,4132)
\n" ); document.write( "M = (y2 - y1)/(x2 - x1) = (4132 - 3432)/(4 - 0) = (700)/4 = 175
\n" ); document.write( "Point-Slope Form:
\n" ); document.write( "\"y+-+y1+=+M%28x+-+x1%29\"
\n" ); document.write( "\"y+-+3432+=+175x\"
\n" ); document.write( "\"-175x+%2B+y+=+3432\"
\n" ); document.write( "\"175x+-+y+=+-3432\"
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