document.write( "Question 443936: Please help me with substitution method !!
\n" ); document.write( "3(2x+y)=4x+20
\n" ); document.write( "x-2y=3
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Algebra.Com's Answer #306135 by chriswen(106)\"\" \"About 
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3(2x+y)=4x+20 ...(i)
\n" ); document.write( "x-2y=3 ...(ii)
\n" ); document.write( "x=3+2y ...(iii)
\n" ); document.write( "...
\n" ); document.write( "Substitute x=3+2y(iii) into (i)
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\n" ); document.write( "3[2(3+2y)+y]=4(3+2y)+20 ... (iv)
\n" ); document.write( "3(6+4y+y)=12+8y+20
\n" ); document.write( "3(6+5y)=32+8y
\n" ); document.write( "18+15y=32+8y
\n" ); document.write( "15y-8y=32-18
\n" ); document.write( "7y=14
\n" ); document.write( "y=14/7
\n" ); document.write( "y=2 ...(v)
\n" ); document.write( "...
\n" ); document.write( "substitute y=2(v) into (iii)
\n" ); document.write( "...
\n" ); document.write( "x=3+2(2) ...(vi)
\n" ); document.write( "x=3+4
\n" ); document.write( "x=7
\n" ); document.write( "...
\n" ); document.write( "Therefore, x=7 and y=2.
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