document.write( "Question 443936: Please help me with substitution method !!
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document.write( "3(2x+y)=4x+20
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document.write( "x-2y=3 \n" );
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Algebra.Com's Answer #306135 by chriswen(106) ![]() You can put this solution on YOUR website! 3(2x+y)=4x+20 ...(i) \n" ); document.write( "x-2y=3 ...(ii) \n" ); document.write( "x=3+2y ...(iii) \n" ); document.write( "... \n" ); document.write( "Substitute x=3+2y(iii) into (i) \n" ); document.write( "... \n" ); document.write( "3[2(3+2y)+y]=4(3+2y)+20 ... (iv) \n" ); document.write( "3(6+4y+y)=12+8y+20 \n" ); document.write( "3(6+5y)=32+8y \n" ); document.write( "18+15y=32+8y \n" ); document.write( "15y-8y=32-18 \n" ); document.write( "7y=14 \n" ); document.write( "y=14/7 \n" ); document.write( "y=2 ...(v) \n" ); document.write( "... \n" ); document.write( "substitute y=2(v) into (iii) \n" ); document.write( "... \n" ); document.write( "x=3+2(2) ...(vi) \n" ); document.write( "x=3+4 \n" ); document.write( "x=7 \n" ); document.write( "... \n" ); document.write( "Therefore, x=7 and y=2. \n" ); document.write( " |