document.write( "Question 443874: Perimeter of a high school basketball court. The perimeter of a standard high school basketball court is 268 ft. The length is 34 ft longer than the width. Find the dimensions of the court.\r
\n" ); document.write( "\n" ); document.write( "Source: Indiana High School Athletic Association\r
\n" ); document.write( "\n" ); document.write( "thank you!
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Algebra.Com's Answer #306104 by chriswen(106)\"\" \"About 
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Let x ft be the width.
\n" ); document.write( "Let x+34 ft be the length.\r
\n" ); document.write( "\n" ); document.write( "P=2(l+w)
\n" ); document.write( "268=2(x+34+x)
\n" ); document.write( "268=2(2x+34) distribution law
\n" ); document.write( "268=4x+68
\n" ); document.write( "4x=268-68
\n" ); document.write( "4x=200
\n" ); document.write( "x=200/4
\n" ); document.write( "x=50
\n" ); document.write( "x+34=84\r
\n" ); document.write( "\n" ); document.write( "Therefore the width of the basketball court is 50ft and the length of the court is 84ft.
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