document.write( "Question 443874: Perimeter of a high school basketball court. The perimeter of a standard high school basketball court is 268 ft. The length is 34 ft longer than the width. Find the dimensions of the court.\r
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document.write( "Source: Indiana High School Athletic Association\r
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document.write( "thank you! \n" );
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Algebra.Com's Answer #306104 by chriswen(106)![]() ![]() ![]() You can put this solution on YOUR website! Let x ft be the width. \n" ); document.write( "Let x+34 ft be the length.\r \n" ); document.write( "\n" ); document.write( "P=2(l+w) \n" ); document.write( "268=2(x+34+x) \n" ); document.write( "268=2(2x+34) distribution law \n" ); document.write( "268=4x+68 \n" ); document.write( "4x=268-68 \n" ); document.write( "4x=200 \n" ); document.write( "x=200/4 \n" ); document.write( "x=50 \n" ); document.write( "x+34=84\r \n" ); document.write( "\n" ); document.write( "Therefore the width of the basketball court is 50ft and the length of the court is 84ft. \n" ); document.write( " |