document.write( "Question 443856: \"3x%5E2-10x=-7\" \n" ); document.write( "
Algebra.Com's Answer #306088 by chriswen(106)\"\" \"About 
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\"3x%5E2-10x=-7\"
\n" ); document.write( "\"3x%5E2-10x%2B7=0\"
\n" ); document.write( "You want to find two numbers that:
\n" ); document.write( "multiply to 7*3=21
\n" ); document.write( "and add to -10
\n" ); document.write( "therefore -3 and -7\r
\n" ); document.write( "\n" ); document.write( "\"3x%5E2-3x-7x%2B7=0\"
\n" ); document.write( "\"3x%28x-1%29-7%28x-1%29=0\"
\n" ); document.write( "\"%283x-7%29%28x-1%29=0\"\r
\n" ); document.write( "\n" ); document.write( "So,
\n" ); document.write( "\"3x-7=0\"
\n" ); document.write( "\"3x=7\"
\n" ); document.write( "\"x=7%2F3\"
\n" ); document.write( "or
\n" ); document.write( "\"x-1=0\"
\n" ); document.write( "\"x=1\"\r
\n" ); document.write( "\n" ); document.write( "So therefore, x=7/3 or x=1 .
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