document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=443823>Question 443823</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write each series in summation notation<BR>\n" );
document.write( "-2 +4 -8 +16 -32 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #306065 by </B><A HREF=/tutors/aboutme.mpl?userid=tinbar><B>tinbar(133)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tinbar><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=306065\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (Sigma):(-2)^n, from n = 1 up to infinity. \r<BR>\n" );
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document.write( "if your question requires you start from n = 0 and go to infinity, then the answer is: (Sigma):(-2)^(n+1) </SPAN>\n" );
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