document.write( "Question 443756: Would you please show me the STEPS to factor the following: 6x^2+12x+6. I know the answer is 6(x+1)^2, I'm just confused as to how to get there. \n" ); document.write( "
Algebra.Com's Answer #306013 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"+6x%5E2%2B12x%2B6+\"
\n" ); document.write( "Divide both sides by \"6\"
\n" ); document.write( "\"+x%5E2+%2B+2x+%2B+1+=+0+\"
\n" ); document.write( "Use the quadratic formula
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "\"a+=+1\"
\n" ); document.write( "\"b+=+2\"
\n" ); document.write( "\"c+=+1\"
\n" ); document.write( "\"x+=+%28-2+%2B-+sqrt%28+2%5E2+-+4%2A1%2A1+%29%29%2F%282%2A1%29+\"
\n" ); document.write( "\"x+=+%28-2+%2B-+sqrt%28+4+-+4+%29%29+%2F+2+\"
\n" ); document.write( "\"x+=+%28-2%29+%2F+2+\"
\n" ); document.write( "\"+x+=+-1+\"
\n" ); document.write( "This is called a double root, since the
\n" ); document.write( "equation must have 2 roots, it has the same
\n" ); document.write( "root twice. Plug it back in for \"x\" to check.
\n" ); document.write( "Rewrite it as:
\n" ); document.write( "\"+x+%2B+1+=+0+\" 1st factor
\n" ); document.write( "\"+x+%2B+1+=+0+\" 2nd factor
\n" ); document.write( "\"+%28x+%2B+1%29%5E2+=+0+\" answer
\n" ); document.write( "Note that after you multiply it out as
\n" ); document.write( "\"+x%5E2+%2B+2x+%2B+1+=+0\"
\n" ); document.write( "Multiplying both sides by \"6\" doesn't change anything
\n" ); document.write( "
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