document.write( "Question 443749: Two trains are 500 miles apart. They start towards eachother at the same time,one's speed is 20 miles per hour faster than the other.Thet meet in 4 hours.How fast is each train going? \n" ); document.write( "

Algebra.Com's Answer #306005 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Think of 1 train as standing still and the other
\n" ); document.write( "heading towards it at the sum of their speeds
\n" ); document.write( "Let the speed of the slower train = $\"s\"$
\n" ); document.write( " $\"+d+=+r%2At+\"$
\n" ); document.write( " $\"+500+=+%28s+%2B+s+%2B+20%29%2A4+\"$
\n" ); document.write( " $\"+500+=+%282s+%2B+20%29%2A4+\"$
\n" ); document.write( " $\"+500+=+8s+%2B+80+\"$
\n" ); document.write( " $\"+8s+=+420+\"$
\n" ); document.write( " $\"+s+=+52.5+\"$
\n" ); document.write( " $\"+s+%2B+20+=+72.5+\"$
\n" ); document.write( "The slower train is going 52.5 mi/hr
\n" ); document.write( "The faster train is going 72.5 mi/hr
\n" ); document.write( "check amswers:
\n" ); document.write( "slower train:
\n" ); document.write( " $\"+d+=+52.5%2A4+\"$
\n" ); document.write( " $\"+d+=+210+\"$
\n" ); document.write( "faster train:
\n" ); document.write( " $\"+d+=+72.5%2A4+\"$
\n" ); document.write( " $\"+d+=+290+\"$
\n" ); document.write( " $\"+210+%2B+290+=+500+\"$
\n" ); document.write( " $\"+500+=+500+\"$
\n" ); document.write( "OK \n" ); document.write( "

\n" );