document.write( "Question 443597: Two drivers leave their houses at the same time. The ﬁrst driver’s car has a gas tank
\n" ); document.write( "that holds 15 gallons. The second has a gas tank that holds 13 gallons. Both cars are
\n" ); document.write( "using up their gasoline at the same rate of 2 gallons per hour. When is the amount of
\n" ); document.write( "gasoline in one tank 7 times the amount of gasoline in the other tank \n" ); document.write( "

Algebra.Com's Answer #305967 by rwm(914) $\"\"$ $\"About$

You can put this solution on YOUR website!
15-2t=7*(13-2t)
\n" ); document.write( "15-2t=91-14t
\n" ); document.write( "12t=76
\n" ); document.write( "t=76/12
\n" ); document.write( "t=38/6
\n" ); document.write( "t=19/3
\n" ); document.write( "t=6 1/3
\n" ); document.write( "15-2(19/3)
\n" ); document.write( "15-38/3
\n" ); document.write( "45/3=38/3=7/3
\n" ); document.write( "13-38/3=
\n" ); document.write( "39/3-38/3=1/3\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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