document.write( "Question 443605: Prove that the sum of the measures of the complements of complementary angles is 90 degrees. \n" ); document.write( "
Algebra.Com's Answer #305913 by swincher4391(1107)![]() ![]() You can put this solution on YOUR website! Let A and B be two complementary angles. We need to show that the complements of these two angles have a sum of 90. Since A and B are complementary. Then A + B = 90. Let C be the complement of A. Then A + C = 90. Let D be the complement of B. Then B + D = 90. So show that C + D = 90. \n" ); document.write( "==============\r \n" ); document.write( "\n" ); document.write( "A + C = 90 and B + D =90\r \n" ); document.write( "\n" ); document.write( "So A = 90 - C and B = 90 - D \n" ); document.write( "================== \n" ); document.write( "Since A + B = 90 \n" ); document.write( "Then 90 - C + 90 - D = 90\r \n" ); document.write( "\n" ); document.write( "180 - C - D = 90 \n" ); document.write( "90 = C + D \n" ); document.write( "======== \n" ); document.write( "Which is what we wanted to show. \n" ); document.write( "============ \n" ); document.write( "Then C (the complement of A) and D(the complement of B) are complements of each other. \n" ); document.write( " |