document.write( "Question 443513: The lenght of the side of a square is increase by 50%. By what % is the area of the square increase. \n" ); document.write( "
Algebra.Com's Answer #305901 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The length of the side of a square is increase by 50%. By what % is the area of the square increase. \n" ); document.write( "------------------------------ \n" ); document.write( "If side = \"s\", area = s^2. \n" ); document.write( "--- \n" ); document.write( "If s is increased by 50% you get (1.5s) \n" ); document.write( "Area will be (1.5s)^2 = 2.25s^2 \n" ); document.write( "--- \n" ); document.write( "Increase = 2.25s^2-s^2 = 1.25s^2 \n" ); document.write( "--- \n" ); document.write( "% increase = (1.25s^2)/s^2 = 1.25 = 125% increase \n" ); document.write( "=============================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |