document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=443380>Question 443380</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please explain step by step c+(4-3c)-2=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #305839 by </B><A HREF=/tutors/aboutme.mpl?userid=Leaf+W.><B>Leaf W.(135)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Leaf+W.><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Leaf+W.><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=305839\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> c+(4-3c)-2=0<BR>\n" );
document.write( "Add 2 both sides: c+(4-3c)-2+2=2<BR>\n" );
document.write( "Simplify -2+2 into 0: c+(4-3c)=2<BR>\n" );
document.write( "Switch the order of the 4 and -3c (Commutative Property for Addition): c+(-3c+4)=2<BR>\n" );
document.write( "Move the parentheses: [c+(-3c)]+4=2<BR>\n" );
document.write( "Add c and -3c: -2c+4=2<BR>\n" );
document.write( "Subtract 4 from both sides: -2c+4-4=2-4<BR>\n" );
document.write( "Simplify 4-4 and 2-4: -2c=-2<BR>\n" );
document.write( "Divide both sides by -2: c=1\r<BR>\n" );
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document.write( "Therefore, c=1. </SPAN>\n" );
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