document.write( "Question 46067: find three consecutive odd integers such that the product of the first and third is 71 more than 10 times the second
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Algebra.Com's Answer #30581 by Nate(3500) $\"\"$ $\"About$

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first integer = i
\n" ); document.write( "second integer = i + 2
\n" ); document.write( "third integer = i + 4
\n" ); document.write( " $\"i%28i+%2B+4%29+=+10%28i+%2B+2%29+%2B+71\"$
\n" ); document.write( " $\"i%5E2+%2B+4i+=+10i+%2B+91\"$
\n" ); document.write( " $\"i%5E2+-+6i+-+91+=+0\"$
\n" ); document.write( " $\"%28x+%2B+7%29%28x+-+13%29+=+0\"$
\n" ); document.write( "x = -7 or x = 13
\n" ); document.write( "-7,-5,-3
\n" ); document.write( "or (you have two answers)
\n" ); document.write( "13,15,17 \n" ); document.write( "

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