document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=443343>Question 443343</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What are all the positive angles Q in degree for which cos Q = square root 3/2? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #305802 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=305802\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Think about your 30º, 60º, 90º triangle.\r<BR>\n" );
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document.write( "Draw a right triangle with angles 30 and 60 to make this easier.\r<BR>\n" );
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document.write( "In a 30,60,90\r<BR>\n" );
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document.write( "The side opposite the 30º is the shortest side, and it is 1.<BR>\n" );
document.write( "The side opposite the 60º is length <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%283%29 ALIGN=MIDDLE  ALT=\"sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "The side opposite the 90º is the hypotenuse (longest side) and it is 2.<BR>\n" );
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document.write( "I really wish I had a picture to make this easier.<BR>\n" );
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document.write( "Try this http://www.google.com/imgres?imgurl=http://www.biology.arizona.edu/BioMath/tutorials/Trigonometric/graphics/trig_30_60_90.gif&imgrefurl=http://www.biology.arizona.edu/BioMath/tutorials/Trigonometric/specialangles.html&h=268&w=393&sz=2&tbnid=0lxAXKWR0X3n7M:&tbnh=85&tbnw=124&prev=/search%3Fq%3D30%2B60%2B90%2Btriangle%26tbm%3Disch%26tbo%3Du&zoom=1&q=30+60+90+triangle&hl=en&usg=__7SUm2hzMWNJUh7c0LUs3K-ybbsY=&sa=X&ei=uM-9TdvSEdKGtwf75ti0BQ&ved=0CC4Q9QEwBQ<BR>\n" );
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document.write( "Anyway, if you know sin(x) = opp/hypo, cos(x) = adj/hypo, tan(x) = opp/hypo, then let's practice.\r<BR>\n" );
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document.write( "cos(60)?  Locate the 60º, Find the adjacent and hypotenuse sides.  You have 1/2. So cos(60) = 1/2<BR>\n" );
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document.write( "So now that we know how to do it,  locate the angle that has adjacent side <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%283%29 ALIGN=MIDDLE  ALT=\"sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > and hypotenuse 2.  That's 30º\r<BR>\n" );
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document.write( "But are we done? \r<BR>\n" );
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document.write( "Remember <BR>\n" );
document.write( "Q1 = All<BR>\n" );
document.write( "Q2 = Sin<BR>\n" );
document.write( "Q3 = Tangent<BR>\n" );
document.write( "Q4 = Cosine\r<BR>\n" );
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document.write( "(All Students Take Classes)<BR>\n" );
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document.write( "This tells us where each trig function is positive.\r<BR>\n" );
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document.write( "We look and see that in Q1 and Q4 cos is positive.\r<BR>\n" );
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document.write( "Locate the angle that lays on the x-axis. This is 360º. Then 360º - 30º = 330º, which is our other angle.<BR>\n" );
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