document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=443328>Question 443328</A>: <I><SPAN STYLE=\"word-break: break-all;\"> From a point on a straight road, John and Fred ride bicycles in opposite directions. John rides 9 miles per hour and Fred rides 13 miles per hour. In how many hours will they be 88 miles apart? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #305792 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=305792\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From a point on a straight road, John and Fred ride bicycles in opposite directions. John rides 9 miles per hour and Fred rides 13 miles per hour. In how many hours will they be 88 miles apart?<BR>\n" );
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document.write( "They are separating at the rate of (9+13) = 22 mph.<BR>\n" );
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document.write( "time = distance/rate<BR>\n" );
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document.write( "time = 88 miles/ 22mph = 4hrs.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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