document.write( "Question 443238: two investments are made totaling $10,000. In one year these investments
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document.write( "yield $650 in simple interest. Part of the $10,000 in invested at 5 1/2%, and
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document.write( "the rest at 6 3/4%. How much more money is invested at 6 3/4%? \n" );
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Algebra.Com's Answer #305746 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! two investments are made totaling $10,000. In one year these investments \n" ); document.write( "yield $650 in simple interest. Part of the $10,000 in invested at 5 1/2%, and \n" ); document.write( "the rest at 6 3/4%. How much more money is invested at 6 3/4%? \n" ); document.write( "---- \n" ); document.write( "2-variable solution: \n" ); document.write( "Quantity Eq. :: x + y = 10,000 \n" ); document.write( "Interest Eq. ::0.055x + 0.0675y = 650 \n" ); document.write( "----------------------------------- \n" ); document.write( "Multiply 1st by 550 \n" ); document.write( "Multiply 2nd by 10000 \n" ); document.write( "------------------------- \n" ); document.write( "550x + 550y = 550*10,000 \n" ); document.write( "550x + 675y = 6400000 \n" ); document.write( "---------------------------------------- \n" ); document.write( "Subtract and solve for \"y\": \n" ); document.write( "125y = 9000000 \n" ); document.write( "y = $7200 (amt invested at 6 3/4%) \n" ); document.write( "=================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |