document.write( "Question 442015: HOW DO YOU SOLVE X+Y=56 AND X+3Y=56 using substitution \n" ); document.write( "
Algebra.Com's Answer #305740 by rwm(914)\"\" \"About 
You can put this solution on YOUR website!
y=0
\n" ); document.write( "Why are you shouting?
\n" ); document.write( "It stands to reason that if have 56 things and take away x I can't y have and 3y
\n" ); document.write( "if y is more than zero
\n" ); document.write( "y=3y
\n" ); document.write( "otherwise we get the absurd
\n" ); document.write( "y/y=3
\n" ); document.write( "which we know can't be.
\n" ); document.write( "y/y must be 1 unless y/y is undefined which is the case if y =0
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