document.write( "Question 442015: HOW DO YOU SOLVE X+Y=56 AND X+3Y=56 using substitution \n" ); document.write( "
Algebra.Com's Answer #305740 by rwm(914)![]() ![]() ![]() You can put this solution on YOUR website! y=0 \n" ); document.write( "Why are you shouting? \n" ); document.write( "It stands to reason that if have 56 things and take away x I can't y have and 3y \n" ); document.write( "if y is more than zero \n" ); document.write( "y=3y \n" ); document.write( "otherwise we get the absurd \n" ); document.write( "y/y=3 \n" ); document.write( "which we know can't be. \n" ); document.write( "y/y must be 1 unless y/y is undefined which is the case if y =0 \n" ); document.write( " \n" ); document.write( " |