document.write( "Question 443190: 25x^4-25x^2+6=0
\n" ); document.write( "i worked the problem out and got x=square root of 3/5 and 2/5 am i doing this right \n" ); document.write( "

Algebra.Com's Answer #305726 by swincher4391(1107) $\"\"$ $\"About$

You can put this solution on YOUR website!
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Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation $\"ax%5E2%2Bbx%2Bc=0\"$ (in our case $\"25x%5E2%2B-25x%2B6+=+0\"$ ) has the following solutons:
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\n" ); document.write( " $\"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"$
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\n" ); document.write( " For these solutions to exist, the discriminant $\"b%5E2-4ac\"$ should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant $\"b%5E2-4ac\"$ : $\"b%5E2-4ac=%28-25%29%5E2-4%2A25%2A6=25\"$ .
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\n" ); document.write( " Discriminant d=25 is greater than zero. That means that there are two solutions: $\"+x%5B12%5D+=+%28--25%2B-sqrt%28+25+%29%29%2F2%5Ca\"$ .
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\n" ); document.write( " $\"x%5B1%5D+=+%28-%28-25%29%2Bsqrt%28+25+%29%29%2F2%5C25+=+0.6\"$
\n" ); document.write( " $\"x%5B2%5D+=+%28-%28-25%29-sqrt%28+25+%29%29%2F2%5C25+=+0.4\"$
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\n" ); document.write( " Quadratic expression $\"25x%5E2%2B-25x%2B6\"$ can be factored:
\n" ); document.write( " $\"25x%5E2%2B-25x%2B6+=+25%28x-0.6%29%2A%28x-0.4%29\"$
\n" ); document.write( " Again, the answer is: 0.6, 0.4.\n" ); document.write( "Here's your graph:
\n" ); document.write( " $\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+25%2Ax%5E2%2B-25%2Ax%2B6+%29\"$

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\n" ); document.write( "\n" ); document.write( "It is not the square root of 2/5 and 3/5, but simply 2/5 and 3/5. \n" ); document.write( "

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