document.write( "Question 443172: If a^3 b^3 c^3=3abc show that either a b c=0 or a=b=c \n" ); document.write( "
Algebra.Com's Answer #305712 by swincher4391(1107)\"\" \"About 
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\"%28abc%29%5E3+-+3abc+=+0\"
\n" ); document.write( "\"abc%28%28abc%29%5E2+-+3%29=+0\"
\n" ); document.write( "Then we have abc = 0
\n" ); document.write( "or
\n" ); document.write( "\"%28abc%29%5E2+=+3\"
\n" ); document.write( "\"%28abc%29+=+sqrt%283%29\"
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\n" ); document.write( "Suppose a = b = c\r
\n" ); document.write( "\n" ); document.write( "Then \"+a%5E3+=+sqrt%283%29\"
\n" ); document.write( " \"+a+=+root%283%2Csqrt%283%29%29\"
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\n" ); document.write( "Plug this back in for a=b=c\r
\n" ); document.write( "\n" ); document.write( "and you get\r
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\n" ); document.write( "\"sqrt%283%29+%2A+sqrt%283%29+%2A+sqrt%283%29+=+3sqrt%283%29\"
\n" ); document.write( "\"3%2Asqrt%283%29+=+3%2Asqrt%283%29\" Check.\r
\n" ); document.write( "\n" ); document.write( "Then \"abc+=0\" or \"a=b=c=root%283%2Csqrt%283%29%29\"\r
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