document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=443177>Question 443177</A>: <I><SPAN STYLE=\"word-break: break-all;\"> make a set of three numbers with a mode of 5 and a mean of 6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #305710 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=305710\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If we have 3 numbers, where the mean is 6 and the mode is 5, then 2 of the numbers have to be 5. Makes sense? If it appeared once, then it could not be the only number that is the mode.  If all three were 5, then the mean would be 5.<BR>\n" );
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document.write( "So, we have :<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%285+%2B+5+%2B+x%29%2F3++=+6 ALIGN=MIDDLE  ALT=\"%285+%2B+5+%2B+x%29%2F3++=+6\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%2B5%2Bx+=+18 ALIGN=MIDDLE  ALT=\"5%2B5%2Bx+=+18\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+8 ALIGN=MIDDLE  ALT=\"x+=+8\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Then our set is {5,5,8}.<BR>\n" );
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