document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=442983>Question 442983</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 5 to the x power = 7 to the 3x-1 power   (solve for X) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #305647 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=305647\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5^x = 7^(3x-1)<BR>\n" );
document.write( "Take the ln of both sides.\r<BR>\n" );
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document.write( "Then xln(5) = (3x-1)ln(7)\r<BR>\n" );
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document.write( "Then 1 =(3x-1)/(x) ln(7)/ln(5)<BR>\n" );
document.write( "1 = (3 - 1/x)ln(7)/ln(5)\r<BR>\n" );
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document.write( "ln(5)/ln(7) = 3 -1/x\r<BR>\n" );
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document.write( "ln(5)/ln(7) -3 = -1/x\r<BR>\n" );
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document.write( "Then <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-1%2F%28ln%285%29%2Fln%287%29-3%29+=+x ALIGN=MIDDLE  ALT=\"-1%2F%28ln%285%29%2Fln%287%29-3%29+=+x\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Or in decimal form: x = 0.46\r<BR>\n" );
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document.write( " </SPAN>\n" );
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