document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=46053>Question 46053</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0618501401/algebrahomeworkh>College Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> I need help finding the center, vertices, and foci for the following equation:\r<BR>\n" );
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document.write( "(x+3)^2/9 + (y+1)^2/16 = 1\r<BR>\n" );
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document.write( "Any help will be greatly appreciated. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #30559 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=30559\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I need help finding the center, vertices, and foci for the following equation:<BR>\n" );
document.write( "(x+3)^2/9 + (y+1)^2/16 = 1 <BR>\n" );
document.write( "STANDARD EQN.OF ELLIPSE IS<BR>\n" );
document.write( "(X-H)^2/A^2 +(Y-K)^2/B^2=1<BR>\n" );
document.write( "CENTRE IS (H,K)..AS PER THE PROBLEM H=-3.....K=-1 HENCE CENTRE OF ELLIPSE IS AT<BR>\n" );
document.write( "IS (-3,-1)<BR>\n" );
document.write( "A=SQRT(9)=3........B=SQRT(16)=4<BR>\n" );
document.write( "WHERE MAJOR AXIS =2B=2*4=8...MINOR AXIS =2A=2*3=6<BR>\n" );
document.write( "ECCENTRICITY =E =SQRT{(B^2-A^2)/B^2}=SQRT{(16-9)/16}=SQRT(7)/4<BR>\n" );
document.write( "FOCI ARE GIVEN BY....(H,K+BE),(H,K-BE)<BR>\n" );
document.write( "(-3,-1+4*SQRT(7)/4),(-3,-1-4*SQRT(7)/4)={-3,-1+SQRT(7)},{-3,-1-SQRT(7)}<BR>\n" );
document.write( "VERTICES ARE (H,K+B),(H,K-B)=(-3,3),(-3,-5)<BR>\n" );
document.write( "AND....(H+A,K),(H-A,K)=(0,-1),(-6,-1) </SPAN>\n" );
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