document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=443029>Question 443029</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2 angles are supplementary. The measure of the smaller angle is 1/2 of the measure of the larger angle. Find the measure of the larger angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #305571 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=305571\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let l +s =180\r<BR>\n" );
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document.write( "Also let s = 1/2l\r<BR>\n" );
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document.write( "2s = l\r<BR>\n" );
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document.write( "2s + s = 180\r<BR>\n" );
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document.write( "3s = 180\r<BR>\n" );
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document.write( "s = 60\r<BR>\n" );
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document.write( "Plug back in:\r<BR>\n" );
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document.write( "l + 60 = 180\r<BR>\n" );
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document.write( "l = 180 -60\r<BR>\n" );
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document.write( "l = 120.\r<BR>\n" );
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document.write( "60 and 120. </SPAN>\n" );
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