document.write( "Question 442956: Find the area of Triangle ABC, if AB=6cm, AC=12cm, and the measure of angle A is 20 degrees. Express your answer to the nearest tenth of a square centimeter. \n" ); document.write( "
Algebra.Com's Answer #305530 by swincher4391(1107)\"\" \"About 
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We know that angle A is opposite BC.\r
\n" ); document.write( "\n" ); document.write( "Let's call side AB and side AC\r
\n" ); document.write( "\n" ); document.write( "We can find what cos(A) is since we know A = 20º\r
\n" ); document.write( "\n" ); document.write( "Let's use the law of cosines.\r
\n" ); document.write( "\n" ); document.write( "Let BC = a, AB = c , AC = b\r
\n" ); document.write( "\n" ); document.write( "a^2 = b^2 + c^2 - 2bc cos(20)\r
\n" ); document.write( "\n" ); document.write( "a^2 = 12^2 + 6^2 - 2(12)(6)cos(20)\r
\n" ); document.write( "\n" ); document.write( "a^2 = 144 + 36 - (144cos(20)\r
\n" ); document.write( "\n" ); document.write( "a^2 = 180 - 144*cos(20º)\r
\n" ); document.write( "\n" ); document.write( "Use your calculator find cos(20º). Make sure your calculator is in DEGREE MODE and not RADIAN MODE.\r
\n" ); document.write( "\n" ); document.write( "a^2 = 180 - 144 * (0.939692621)
\n" ); document.write( "a^2 = 44.6842626
\n" ); document.write( "a = 6.68462883\r
\n" ); document.write( "\n" ); document.write( "We know that (1/2)(a)(b) gives us the area.\r
\n" ); document.write( "\n" ); document.write( "We have a and we have b.\r
\n" ); document.write( "\n" ); document.write( "(1/2)(6.68462883)(6) = 20.053888565 cm.\r
\n" ); document.write( "\n" ); document.write( "\"20.1\"cm when rounded.\r
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