document.write( "Question 442929: There are 8 blue, 3 green, and 10 yellow socks in a drawer. You randomly choose one, then another, without replacement. Find the probability of choosing two blue socks \n" ); document.write( "
Algebra.Com's Answer #305522 by swincher4391(1107)![]() ![]() You can put this solution on YOUR website! Let's count how many socks we have all together:\r \n" ); document.write( "\n" ); document.write( "8 + 3 + 10 = 21.\r \n" ); document.write( "\n" ); document.write( "We have \n" ); document.write( "\n" ); document.write( "Now how many blue socks do we have?\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So we have a \n" ); document.write( "\n" ); document.write( "We take a blue sock and we don't replace it. \n" ); document.write( "How many socks do we have left? 20. How many blue socks do we have left? 7.\r \n" ); document.write( "\n" ); document.write( "We have a 7/20 chance of drawing a blue sock.\r \n" ); document.write( "\n" ); document.write( "So what is P(Blue Sock and Another Blue Sock) = P(Blue Sock) * P(Another Blue Sock) = (8/21) * (7/20)\r \n" ); document.write( "\n" ); document.write( "Let's simplify this:\r \n" ); document.write( "\n" ); document.write( "To make this easier, let's take each term into it's prime decomposition. This is if you have trouble simplifying fractions.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you aren't comfortable with that, then just multiply it straight out \n" ); document.write( " \n" ); document.write( " |