document.write( "Question 442927: i need help with this problem\r
\n" ); document.write( "\n" ); document.write( "divide 56 into two parts such that 3/8 of the larger number decreased by 6 equals 1/4 of the smaller number.
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Algebra.Com's Answer #305520 by swincher4391(1107)\"\" \"About 
You can put this solution on YOUR website!
So let's let the two parts be x and y. Let x be the larger number.\r
\n" ); document.write( "\n" ); document.write( "Then \"x%2By+=+56\" and \"expr%283%2F8%29x-6+=+expr%281%2F4%29y\"\r
\n" ); document.write( "\n" ); document.write( "You have yourself a system of equations. Two unknowns, two equations. It's solvable.\r
\n" ); document.write( "\n" ); document.write( "x+y = 56 ---> x = 56 -y\r
\n" ); document.write( "\n" ); document.write( "Then\r
\n" ); document.write( "\n" ); document.write( "\"expr%283%2F8%29%2A%2856-y%29+-6+=+expr%281%2F4%29y\"
\n" ); document.write( "\"21+-+expr%283%2F8%29y+-6+=+expr%281%2F4%29y\"
\n" ); document.write( "\"15+-+expr%283%2F8%29y+=+expr%281%2F4%29y\"
\n" ); document.write( "Let's multiply everything by 8.
\n" ); document.write( "\"120-+3y+=+2y\"
\n" ); document.write( "\"120+=+5y\"
\n" ); document.write( "\"y+=+24\"\r
\n" ); document.write( "\n" ); document.write( "\"x+%2B+24+=+56\" based on our first equation.
\n" ); document.write( "\"x+=+56-24+=+32\"\r
\n" ); document.write( "\n" ); document.write( "So our numbers are 32 and 24.\r
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